(4x-12)^1/2+(8+4x)^1/2=(16x-12)^1/2

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Solution for (4x-12)^1/2+(8+4x)^1/2=(16x-12)^1/2 equation: 


x in (-oo:+oo)

((4*x-12)^1)/2+((4*x+8)^1)/2 = ((16*x-12)^1)/2 // - ((16*x-12)^1)/2

((4*x-12)^1)/2+((4*x+8)^1)/2-(((16*x-12)^1)/2) = 0

(4*x-12)/2+(4*x+8)/2-((16*x-12)/2) = 0

(4*x-12)/2+(4*x+8)/2+(-1*(16*x-12))/2 = 0

4*x-1*(16*x-12)+4*x-12+8 = 0

8*x-16*x-4+12 = 0

8-8*x = 0

(8-8*x)/2 = 0

(8-8*x)/2 = 0 // * 2

8-8*x = 0

8-8*x = 0 // - 8

-8*x = -8 // : -8

x = -8/(-8)

x = 1

x = 1

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